In the figure, O is the centre of the circle and PT is a tangent at T. If PC = 3 cm and PT = 6 cm,
then calculate the radius of the circle. plz see the attach file
Answers
Answered by
2
HEY DEAR ... ✌️
_______________________
_______________________
In the figure, OPT is a right angled triangle,
right angled a T (As PT is a tangent).
So, let OT and OC be r.
Thus, r² + PT² = OP²
or, r² + 6² = (r+3)²
or, r² + 36 = r² + 6r + 9
or, 6r + 9 = 36 (Cutting off r² from both sides)
or, 6r = 27
or, r = 27/6 = 9/2 = 4.5cm
HOPE , IT HELPS ... ✌️
_______________________
_______________________
In the figure, OPT is a right angled triangle,
right angled a T (As PT is a tangent).
So, let OT and OC be r.
Thus, r² + PT² = OP²
or, r² + 6² = (r+3)²
or, r² + 36 = r² + 6r + 9
or, 6r + 9 = 36 (Cutting off r² from both sides)
or, 6r = 27
or, r = 27/6 = 9/2 = 4.5cm
HOPE , IT HELPS ... ✌️
Similar questions