Question

In the figure, O is the centre of the circle, angle AOC=144 degree and angle APC =145 degree

Answer 1

Answer:

∠ADC=  

2

1

​

∠AOC

(Angle subtended by a chord on mayor area is half of that subtended on center)

∴∠ADC=  

2

1

​

×130=65  

∘

 

Now, ADCB is cyclic quadrilateral ⇒  

Sum of opposite Angles is 180  

∘

 

∴∠ABC+∠ADC=180  

∘

 

∠ABC+65=180  

∘

 

∠ABC=115  

∘

Step-by-step explanation: