Question

in the figure 'o' is the centre of the circle Angle OAB = 50° the measure of angle APC will be​

Answer 1

Answer:

(c). m∠APC = 50°

Step-by-step explanation:

I assume BC is diameter.

ΔAOB is isosceles (OB = OA = r).

m∠OAB = m∠OBA = 50° ⇒ m∠AOB = 80°

Measure of the arc AB = 80° ⇒ measure of the arc AC = 100° ⇒ m∠APC = 100° ÷ 2 = 50°