Question

in the figure,O is the centre of the circle. angle OAB and angle OCB are 30 and 40 respectively.find angle AOC.........PLEASE ANSWER AS FAST AS POSSIBLE

Answer 1

as OA=OB[radius] ,, so angle of OAB=OBA=30°,. then OC=OB, so angle OCB=OBC=40°. next angleOBA+angleOBC=70°=angleABC , as we know that - angle ABC=2×angleAOC. so angleAOC=70°×2=140°

Answer 2

Answer:

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Step-by-step explanation:

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