Question

in the figure o is the centre of the circle . BC=OA , angle OAB = 20 degree and angle AED = 120 degree.
Find the value of angle CFD.

Answer 1

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Answer 2

∠CFD =  80° if in the figure o is the centre of the circle . BC=OA , ∠OAB = 20°and∠AED = 120°

Step-by-step explanation:

OA = OB  = Radius

in Δ OAB

OA = OB

=> ∠OAB = ∠OBA = 20°

in ΔOBC

OB = OC = Radius

CB = OA given = Radius

=> OBC is an equilateral triangle

=> ∠CBO = 60°

∠FBE = ∠CBO - ∠ABO

=> ∠FBE = 60° - 20°

=> ∠FBE = 40°

∠AED =  ∠FBE + ∠BFE

120° = 40° + ∠BFE

=> ∠BFE = 80°

∠CFD = ∠BFE

=> ∠CFD =  80°

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