Math, asked by deebyan, 10 months ago

In the figure, O is the centre of the circle.
Calculate the magnitudes of AngleAPC
(A) 790
(B) 32°
(C) 47°
(D) 34.50

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Answers

Answered by thewardstricks
5

Answer: (A) 79°

Step-by-step explanation:

Construct a line PO.

In ΔOPA,

OP = OA (Radii)

Since 2 sides of a triangle are equal, the triangle is isosceles.

∠OAP = 32° (Given)

∠APO = 32° (Isosceles Triangle Property)

∠APO = 180 - (32 + 32) (Angle Sum Property)

           = 180 - 64

           = 116°

In ΔOCP,

OP = OC (Radii)

Since 2 angles of the triangle are equal, the triangle is isosceles.

∠OCP = 47° (Given)

∠CPO = 47° (Isosceles Triangle Property)

∠POC = 180 - 47 + 47 (Angle Sum Proptery)

           = 180 - 94

           = 86°

r∠AOC = 116 + 86

r∠AOC = 202°

∠AOC = 360 - 202 (Complete Angle)

∠AOC = 158°

∠APC = 158/2

∠APC = 79°

Answered by aishwaryjain333
0

Answer:

79

Step-by-step explanation:

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