Question

In the figure O is the centre of the circle. If AB and
AC are tangents to the circle and ZBOC = 110°
find the measure of ZOAB.​

Answer 1

Answer: OA will be angle bisector for ZBOC.

So ZAOB=55°

ZOBA=90°(the tangent at any point of a circle is perpendicular to the radius through the point of contact)

Now, by using angle sum property of triangle

ZAOB+ZOBA+ZOAB=180°

ZOAB=180°-145°

ZOAB=35°