Question

In the figure O is the centre of the circle. If angle OPR=30, OQR=40, then find angle poq

Answer 1

Answer:

We know, the angle subtended by an arc of a circle at the centre is double the angle subtended by it at any point on the remaining part of the circle

Hence, In given circle,

ZPOR=2/P QR

Therefore /P OR=2 x 40° =80°