Question

In the figure O is the centre of the circle.If PT is the tangent and PTO=90°,then find POT

Answer 1

Correct Question :- O is the centre of the circle.If PT is the tangent and TPO = 25° .

To Find :- angle POT = ?

Solution :-

since PT is tangent to the circle .

so, in ∆POT we have,

→ ∠OTP = 90° { Tangent is perpendicular to the radius .}

and,

→ ∠TPO = 25° { given }

then,

→ ∠OTP + ∠TPO + ∠POT = 180° { By angle sum property. }

→ 90° + 25° + ∠POT = 180°

→ 115° + ∠POT = 180°

→ ∠POT = 180° - 115°

→ ∠POT = 65° (Ans.)

Note :- If we assume ∠PTO = 90° . it will be between tangent and radius . But with this data alone we can only find sum of rest two angles , which is also 90° .

Learn more :-

PQ and XY are two chords of a circle such that PQ = 6 cm and XY = 12 cm and PQ||XY. If the distance between the chords i...

https://brainly.in/question/24793483

PQRS is a cyclic quadrilateral with PQ = 11 RS = 19. M and N are points on PQ and RS respectively such that PM = 6, SN =...

https://brainly.in/question/27593946

Answer 2

1}If the figure ‘O’is the center of the circle PT is the tangent . If angel =30° then angel POT is

a}30° b}60° c}90° d}120°

Ans:c}90°