in the figure, o is the centre of the circle <CBD=65°.
calculate x and y.
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Angle ABC = 180° - 65° (Linear Pair)
Angle ABC = 115°
Angle x = 2(Angle ABC) (Theorem 10.8 :- The angle subtended by arc at the centre is double than angle subtended by it at any point on the remaining part of the circle )
Angle x = 2(115) = 230°
Angle AOC = 360° - 230°
Angle AOC = 130°
Angle y = 130°/2 ( Theorem 10.8:- The angle subtended by arc at the centre is double than angle subtended by it at any point on the remaining part of the circle )
Angle y = 65°
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