Question

In the figure, O is the centre of the circle, mAOB = 28˚ and mCOD = 58˚.
Find:
1. m (arc CYD)
2. m (arc AMB)
3. m (arc ADC)
4. m (arc BC)

Answer 1

Answer:

Given radius=28 cm, θ=45∘

Area of minor segment = Area of sector OAB - Area of ΔOAB

Area of sector OAB = 360πr2×θ=(722×3601×(28)2×45)cm2=308cm2

Area of ΔOAB=21×OA×OB×sin45∘[∵AreaofΔABC=21AB×AC×sinA]

=21×28×28×21cm2=14×14×2cm2

=196×1.414cm2=277.144cm2

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

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