in the figure ,O is the centre of the circle .OM = 3 cm and AB = 8 cm . Find the radius of the circle
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OM=3cm
AB=8cm =>AM=MB = 4cm
using Pythagoras theorem in ∆AOM,
AO²=AM²+OM²
AO²=4²+3²
AO=√(16+9)=√25 = 5cm
Radius is 5 cm
AB=8cm =>AM=MB = 4cm
using Pythagoras theorem in ∆AOM,
AO²=AM²+OM²
AO²=4²+3²
AO=√(16+9)=√25 = 5cm
Radius is 5 cm
sushant2505:
please mark as brainliest
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HERE IS YOUR REQUIRED ANSWER....PLEASE SEE THE ATTACHED PICTURE
REGARDS
KHUSHI :)
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sorry dear my answer is wrong I took 8 instead of 4 so please check that and solve it by putting 4 over there.....and please mark brainliest and once again sorry for the mistake :(
It's Wrong Dude.
if you will put 4 instead of 8 then it will be right by mistake I wrote there 8...check it I also wrote in my comment
Yes ,you are right dude!
I know that i am right chirag ;)...xD
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