Question

in the figure O is the centre of the circle prove that angle aoc is equal to angle AFC + angle AEC

Answer 1

Now, ∠ABC = ∠ADC.

So, ∠AFC = 2∠ABC = ∠ABC + ∠ADC

= 180° - ∠EBF + 180° - ∠EDF

= 360° - ∠EBF - ∠EDF

= ∠BED + ∠BFD

= ∠AEC + ∠AFC, as required.

Please mark as brainliest thanks :)

Answer 2

Answer:

Step-by-step explanation: