In the figure, O is the centre of the circle. Seg AB
is the diameter. At the point C on the circle the
tangent CD is drawn. Line BD is a tangent to the
circle at the point B.
Show that seg OD | chord AC.
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Answered by
17
Answer:
Please adjust. My phone is damaged but I triedmy best
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Answered by
8
seg OD || chord AC
Step-by-step explanation:
in Δ OCD & Δ OBD
OC = OB ( radius)
CD = BD ( common tangent)
OD = OD common
=> Δ OCD ≅ Δ OBD
=> ∠COD = ∠BOD
in ΔAOC
OA = OC ( radius)
=> ∠OCA = ∠OAC
∠COB = ∠OCA + ∠OAC ( extriore angle of ΔAOC)
=> ∠COD + ∠BOD = ∠OCA + ∠OCA
=> ∠COD + ∠COD = 2∠OCA
=> 2∠COD = 2∠OCA
=> ∠COD = ∠OCA
=> AC ║ OD ( alternate angle)
QED
Proved
Learn more:
solve the problem... - Brainly.in
brainly.in/question/8840598
In figure 3.51, in ΔABC, seg AD and seg BE are altitudes and AE ...
brainly.in/question/4559688
https://brainly.in/question/8727278
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