in the figure O is the centre of the circle, triangle QPR is an isoscles triangle with PQ=OR & angle PQR=40°.Find the measure of angle QSR ,angle QTR & angle QOR
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hey dear,
here is your answer
<PQR=<PRQ(isocles triangle)
<QPR=180-(40+40)
=100
<QTR=180-<QPR (sum of the opposite angles of a cyclic quadrilateral is 180)
=180-100
=80
<QOR=2 x <QTR (angle substended in the circumference is half of the angle at center)
=2 x 80
= 160
<QSR=<QPR (corresponding angles are equal)
= 100
Hope it helped you
thankz
########################################################
here is your answer
<PQR=<PRQ(isocles triangle)
<QPR=180-(40+40)
=100
<QTR=180-<QPR (sum of the opposite angles of a cyclic quadrilateral is 180)
=180-100
=80
<QOR=2 x <QTR (angle substended in the circumference is half of the angle at center)
=2 x 80
= 160
<QSR=<QPR (corresponding angles are equal)
= 100
Hope it helped you
thankz
########################################################
kaira6:
thx
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