Question

in the figure O is the centre of the circle. What is the value of x​

Answer 1

Answer:

X=75 ( by theorem as we know that radius is double then the point of circle.)

Answer 2

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To find :-

Value of x

Given :-

∠AOC=150°

SOLUTION:-

∠AOC= 2×∠ADC [Angle substend at the circle is double the angle substend at the circumference]

⟹∠AOC=2×∠ADC

⟹150°=2×∠ADC

⟹∠ADC=75°

In quadrilateral ABCD,

∠ADC+∠ABC=180°. [ Sum of opposite side of quad. is 180°]

⟹∠ADC+∠ABC=180°.

⟹75°+∠ABC=180°

⟹∠ABC=105°

⟹x=105°

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