in the figure O is the of the circle and arc ABC subtends an angle of 130 degree at the centre. if AB is extended to P find angle PBC
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richadwivedi15:
Ok
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You already know the answer....
yes but how i will do
I think this can be a hint which can help you
please
Extend the line AO and name that point R and then drop perpendicular to AP also, extend OC from where the perpendicular line will also pass and hence angle ARP will be 40 degree and angle RAP hence comes to be 50 degree
And then join BCR which I thought will bisect the angle R and hence by summation of all angles of triangle = 180° angle CBP or angle RBP comes out to be 70°
ok thanks
Its OK but my answer is wrong
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75° will be the correct ans from my side
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