in the figure,o marks the centre of the circle. find the size of each unknown (lettered) angle.
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Step-by-step explanation:
draw line OM
to form two triangles MCO and MBO
MC=MB(given)
MOB=MOC=90°(OM perpendicular bisector)
OM=OM(common)
triangles MCO is congruent to MBO(RHS)
OMB=OMC (CPCT)
OM=OC (radii)
MCO=MBO(opposite angles are equal)
MCO
angle sum property MCO
x+90+1=180
angle sum property MBO
y+90+2=180
2x+m=180
180-2x=m
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