Question

In the figure , OA and OB are opposite rays.

i) If angle BOC = 75°, find angle AOC.

ii) If angle AOC = 110° , find angle BOC.


⬆️Diagram is in the attachment⬆️

❌No irrelevant answers❌​

Answer 1

1. Since AOB is a straight line

there fore, angle AOC + angle BOC = 180

( sum of angles on a straight line is 180)

AOC + 75 = 180

AOC = 180 - 75

therefore AOC = 105

2. similarly, 110 + BOC = 180

BOC = 180 - 110

therefore BOC = 70

I hope it helps you armii

purple you

Answer 2

ANSWER ⤵️

➠ Q. If angle BOC = 75°, find angle AOC.

⠀ ⠀⠀ ⠀⠀ ⠀⠀ ⠀ ⋆ ANSWER ⋆

GIVEN : 1. OA and OB are opposite rays.

2. BOC = 75°

What theorem says ?

⋆ opposite rays of 2 angle makes a straight line

→ so angle ∠AOC and ∠COB makes a line

SOLUTION :-

∵ we know that AOB is a line so ,

∠AOC + ∠COB = 180° ( already proven )

here , ∠BOC or ∠COB = 75°

SO,

∠AOC + 75° = 180°

∠AOC = 180° - 75°

∴∠AOC = 105°

━━━━━━━━━━━━━━━━━━━━

➠ Q. If angle AOC = 110° , find angle BOC

⠀ ⠀⠀ ⠀⠀ ⠀⠀ ⠀ ⋆ ANSWER ⋆

GIVEN : 1. OA and OB are opposite rays.

⠀ ⠀⠀ ⠀ 2. AOC= 110°

What theorem says ?

⋆ opposite rays of 2 angle makes a straight line

→ so angle ∠AOC and ∠COB makes a line

SOLUTION :-

∵ we know that AOB is a line so ,

∠AOC + ∠COB = 180° ( already proven )

here ∠AOC = 110°

so putting the value in place

110° + ∠COB = 180

∠COB = 180° -110°

∴∠COB= 70°

$\color{purple}{HOPE}$ $\color{purple}{THIS}$ $\color{purple}{WILL}$ $\color{purple}{HELPS}$ $\color{purple}{YOU}$