Question

In the figure, OAB is a quadrant of a circle of radius 7cm. Calculate the perimeter of the quadrant taking π = 22/7. *

Answer 1

Answer:

Step-by-step explanation:

Perimeter of quadratic circle =1/4(2πr)

r=7

1/4[2(22/7)(7)]

1/4[44/7(7)]. 7&7 get cancel

1/4(44)

=11

Therefore perimeter of quadratic circle is 11

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Answer 2

Answer:

$\large\boxed{Perimeter\:of\:the\:Quadrant\:OAB=5.5\:cm}$

Step-by-step explanation:

★Given:-

   OAB is a Quadrant with radius 7 cm. π=$\frac{22}{7}$

★To Find:-

  Perimeter of the Quadrant OAB.

★Formula Applied:-

   Length of an arc of a sector of angle θ= (θ/360)×2πr

★Solution:-

Length of an arc of a sector of angle θ= (θ/360)×2πr ,where θ=90°and r=7 cm.

⇒Perimeter of the Quadrant OAB=$\frac{90}{360}\times\frac{22}{7} \times7$

⇒Perimeter of the Quadrant OAB=$\frac{22}{4}\:cm$

⇒Perimeter of the Quadrant OAB=$\frac{11}{2}\:cm$

$\implies\boxed{Perimeter\:of\:the\:Quadrant\:OAB=5.5\:cm}$