In the figure OAB is an equilateral triangle.If O is the central of circle,find measure of <ACB.
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samir647:
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in OAB
since OAB is an equilateral triangle
m<O=m<A= m<B = 60°----- eq 1
InABC
m<A +m<B + m< C = 180° (Sum of measure of all angle of triangle)
60° + 60° + m<C = 180° ------ from eq 1
120 + m<C = 180
m<C = 180- 120
m<C = 60°
m< ACB = 60°
since OAB is an equilateral triangle
m<O=m<A= m<B = 60°----- eq 1
InABC
m<A +m<B + m< C = 180° (Sum of measure of all angle of triangle)
60° + 60° + m<C = 180° ------ from eq 1
120 + m<C = 180
m<C = 180- 120
m<C = 60°
m< ACB = 60°
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