In the figure of ∆ABC, D divides CA in the ratio 4 : 3. If DE || BC, then find
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Answer:
Step-by-step explanation:
33:49
ED||BC
∠AED=∠ABC
∠ADE=∠ACB
INΔABC AND ΔAED
WE HAVE
∠AED=∠ABC
∠ADE=∠ACB
SO ΔAED~ΔABC
ae/ab=ed/bc=ad/ac
ed/bc=ad/ac
ad/dc=4/3
dc/ad=3/4
dc/ad+1=3/4+1
ac/ad=7/4
ad/ac=4/7
froam e(1)
ed/bc=4/7
ratio of areas of two similar triangle is equal to the square of ratios of their corresponding sides
ar(aed)/ar(abc)=(4/7)^2
ar(Abc)-ar(bcde)/ar(abc)=16/49
49ar(abc)-49ar(bcde)=16ar(abc)
33ar(abc)=49ar(bcde)
ar (bcde)/ar(abc)=33/49
ar (bcde):ar(abc)=33:49
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