In the figure of ABCD is a rhombus
Find the measure of the following angles If angle ACB equal 30 degree
a: angle BOC
b: angle AOD
c: angle OAD
d: angle ABO
Answers
Answered by
1
Answer:
where is the figure. Then I will answer it
Answered by
0
Answer:
From the figure:-
∠DAO=∠BCO (Alternate interior Angle)
=30
o
(Two parallel lines are crossed by a transversal)
We know that Diagonals in a rhombus intersect at right angle so ∠BOC=90 …………..(1)
through vertically opposite Angles AOD=90
o
Now takes ΔBOC
∠BOC+∠OCB+∠CBO=180
o
90
o
+30
o
+∠CBO=180
o
∠CBO=180−120
o
∠CBO=60
o
……………(2) Ans
∠OCB=∠OAD (Alternate interior Angle)
=30
o
…………..(3) Ans
All the four triangle should be similar by this in ΔAOB.
∠AOB=90
o
∠OAB=30
o
∠ABO=60
o
.
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