Question

In the figure of DC=DB,AE//CB and CE bisects DCB, AB bisect DBC. Prove that AB=CE​

Answer 1

Answer:

<BCE = <E( Alt angle)

<CBA= <A( Alt angle)

<BCE = <CBA(Given)

<A = <E

In ∆ABD &∆ECD,

<ABD = <ECD( GIVEN)

DB=DC(GIVEN)

<A=<E (PROOVED)

∆ABD is congruent to ∆ECD(ASA Axiom )

AB = CE

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