Math, asked by Akashtiwari4462, 1 year ago

In the figure of PQR is the tangent to a circle at Q whose centre is O AB is a chord parallel to PR and angle BQR is 70 degree than what is angle AQB

Answers

Answered by Anonymous
4
Given:

PQR is a tangent

AB II PR

angle BQR = 70

so ∠BAQ = ∠BQR = 70 ( alternate angles)

and ∠ABQ = ∠BQR = 70 ( as AB II PR)

by summing all the angles 

∠BAQ + ∠ABQ +∠AQB= 180

∠AQB = 180 - 70 -70

= 40 
Answered by divyanshi261
0
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