Question

In the figure of triangle ABC, DE
is parallel to AB. If AD=2x,DC=x+3,BE=2x-1 and CE=x,then find the value of x

Answer 1

Answer:

Step-by-step explanation:

Since, ABC~DEC(AAA)

=>CD/CA=CE/CB

=>x+3/x+3+2x=x/x+2x-1

=>x+3(3x-1)=x(3x+3)

=>3x^2-x+9x-3=3x^2+3x

=>8x-3=3x

=>8x-3x=3

=>5x=3

=>x=3/5