Question

In the figure , os is perpendicular to the chord PQ of a circle whose centre is O. If QR is a diameter , show that QP = 2OS

Answer 1

With the given conditions, it is not possible to prove that QP = 2OS.

We can just prove that PR = 2OS.



In ΔPQR,

O is the mid point of QR (since O is the center of circle)

Also, S is the mid point of PQ. (radius perpendicular to chord bisects the chord)

Now, using mid point theorem,

We can say that OS =½pr

pr =2Os

Answer 2

Answer:

Step-by-step explanation:

With the given conditions, it is not possible to prove that QP = 2OS.

We can just prove that PR = 2OS.

In ΔPQR,

O is the mid point of QR (since O is the center of circle)

Also, S is the mid point of PQ. (radius perpendicular to chord bisects the chord)

Now, using mid point theorem,

We can say that OS =½pr

pr =2Os