In the figure out is the centre of the circle and PA=PB find angleOPA
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Join OA and OB
In △OAP and △OBP
OA=OB(radii of same circle)
AP=BP(Given)
OP=OP(Common)
These triangles are congruent by SSS rule
Angle OPA = Angle OPB(cpct)
Angle OPA+Angle OPB=180(linear pair)
Angle OPA = Angle OPA=180
2angleOPA =180
Angle OPA = 90°
Varun1870:
Is my answer correct
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hope the given pic would help.... :)
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