Question

in the figure P is any point on the digonal AC of the parallelogram ABCD . show that ar(triangeADP) =ar (triangle ABP)

Answer 1

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Answer 2

Let, perpendicular from D and B on AC be h1 and h2 respectively.

We know, ar (ADC) = ar (ABC)

1/2 AC* h1 = 1/2 AC * h2

So, h1 = h2

ar (APD) = 1/2 AP * h1

ar (ABP) = 1/2 AP * h2

Hence, ar (ADP) = ar (ABP)

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