Question

In the figure P is the
centre and A and B
are the endpoints of
diameter of circle. C is
a point of the circle
such that ABC = 35°.
Determine angle BAC,
angle PCB and anglePCA.
​

Answer 1

Answer:angleBAC is 35 degree

anglePCA is 55 degree

anglePCA is 55 degree

Step-by-step explanation:

join p,c; p,a ;b,c and a, c

pc ,ap ,bp are radii of the circle so triangle bpc and triangle pac are isoscles triangles so angle pbc is equal to ange pcb which is 35 degree . Therefore angle bpc is 110 degree. Again angle cpa is equal to 180- angle bpc which is equal to 70 degree. Then in triangle pac angle pca and angle pac is equal to 180- angle cpa i.e. 70 divided by 2 which is 55 degree. Since triangle cpa is an isoscles triangle

Hope its helpful

Answer 2

Answer:

sorry I don't know answer sorry mate