Math, asked by vaibhavikhalkar59, 11 months ago

In the figure P is the
centre and A and B
are the endpoints of
diameter of circle. C is
a point of the circle
such that ABC = 35°.
Determine ZBAC,
ZPCB and ZPCA.
guys my boards r there pls answer in detailed explanation..

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Answers

Answered by kulwantigju
6

Step-by-step explanation:

BAC= 180⁰- 90-35=55⁰ (angle in semicile is 90⁰)

BAC=35⁰ (PB=PC radius of circle)

PCA= 55⁰ ( isosceles triangle)

Answered by shindedropadi
4

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