In the figure P is the mid point of BC , D is the mid point of AP.
a) If the area of the coloured part is 10 sq.cm then what is the area of triangle AP C.
b) What is the area of triangle AP B?
c) What is the area of triangle ABC?
Answers
Given : P is the mid point of BC , D is the mid point of AP.
area of the coloured part is 10 sq.cm
To Find: area of triangle APC
area of triangle APB
area of triangle ABC
Solution:
P is the mid point of BC
Hence Area of ΔABP = area of Δ APC = (1/2) Area of ΔABC
D is the mid point of AP.
=> Area of ΔADC = area of Δ PDC = (1/2) Area of ΔAPC
Area of ΔADC = 10 cm²
=> 10 = (1/2) Area of ΔAPC
=> Area of ΔAPC = 20 cm²
Area of ΔABP = area of Δ APC = 20 cm²
area of Δ APC = (1/2) Area of ΔABC
=> 20 = (1/2) Area of ΔABC
=> Area of ΔABC = 40 cm²
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