In the figure P is the midpoint of BC. AB and CD are parallel. a) Prove that AB = CD b) P is the midpoint of AD. B D
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Given:- AB∣∣DC
To prove : - P is midpoint of AC
Proof :- P is midpoint of DB.
Here DP=BP.
∴∠DCP=∠BAP.
and ∠DPC=∠APB
DP=BP
∴ now ΔDPC≅ΔAPB
∴∠CDP=∠PBA
∴AP=PC
∴AP+PC=AC [we know]
2AP=AC
[AP=
2
AC
]
∴P is midpoint of AC
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