In the figure PA and PB are tangents of a circle with Centre O if angle APB = 50 degree find the angle of AOB
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∠AOB = 130° if PA & PB are tangent to Circle with Center O & ∠APB = 50°
Step-by-step explanation:
AOBP is a quadrilateral
Sum of angles of a Quadrilateral = 360°
=> ∠PAO + ∠AOB + ∠PBO + ∠ABP = 360°
∠ABP = 50° given
∠PAO = ∠PBO = 90° as PA & PB are Tangent
=> 90° + ∠AOB + 90° + 50° = 360°
=> ∠AOB = 130°
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Answer:Angle OAB is 25°
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