In the figure PA=PD. Also AB=BC=CD
(a) IF A=50°, then angle D= ?
(b) PB=5 cm, what is the length of PC, why?
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In △APB and △DPC, we have
∠A=∠D=90∘ and
∠APB=∠DPC [Vertically opposite angles]
Thus, by AA-criterion of similarity, we have
△APB∼△DPC
⇒ DPAP=PCPB
⇒ AP×PC=DP×PB [Hence proved]
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