Question

In the figure, PAC and PBC are congruent due to which criteria? a RHS b SAS C. SSS d. ASA​

Answer 1

Answer:

SAS

Step-by-step explanation:

In ∆ APC and ∆BPC

PA= PB = 10m

We know that when two inclined sides of a ∆ (PA and PB) are equal, it is an isosceles ∆.

Hence, angle PAC= PBC = 60°

Now,

Angle ACP = angle BCP = 90°

Therefore,

Angle APC = Angle BPC = 180° - ( 60° + 90°)

= 30°

angle APC = angle BPC = 30°

PC = PC ( Common side).

Now,

PA = PB = 10m ( equal inclined sides)

Angle APC = Angle BPC = 30°

PC = PC ( Common side)

Hence,

∆APC is congruent to ∆ BPC ( By SAS criteria)

Hope it helps :)