Question

In the figure, PAT is tangent at A. If angle ACB = 50° , find (i)angle TAB ​

Answer 1

Answer:

50°

in fig.ABC =90°

50+90+x =180

x=40°

AT is tangent so , TAC =90°.

90-40=50°

hence ans is 50°

Answer 2

Answer:

Measures of the angle of ∠TAB is 90°

Step-by-step explanation:

As per the question we have given that PAT is a tangent and ∠ACB = 50°

In given circle

CA is diameter of circle. Therefore,

∠ABC = 90°

Angle in a semicircle is always a 90°

Now, In ΔABC

∠CAB + ∠ABC + ∠BCA = 180°

Sum of all angle in a triangle is 180°

∠CAB + 90° + 50° = 180°

∠CAB = 180° - 140°

∠CAB = 40°

Now,

∠CAB = 90°

A line drawn from the centre of a circle to the tangent is always perpendicular to the tangent.

∠CAB + ∠TAB = 90°

40° + ∠TAB = 90°

∠TAB = 90° - 40°

∠TAB = 50°

Therefore, the measure of the angle of ∠TAB is 90°