Question

in the figure ,pm = pn , pm perpendicular ab and pn perpendicular ac. proof ab bisect angle bac ​

Answer 1

Step-by-step explanation:

in triangle NAP & triangle PAM

angle PNA = angle PAM = 90 degree

side PN = side PM

side AP =side AP ( common )

then,

s-s-a rules

triangle NAP & triangle PAM are coherence

so, angle NAP = angle PAM

it means AP bisects angle BAC