Question

in the figure ,pm = pn , pm perpendicular ab and pn perpendicular ac. proof ab bisect angle bac ​

Answer 1

Step-by-step explanation:

in ∆AMP and ∆ANP,

PN = PM (Given)

angle N = angle M= 90°

AP = PA (common side)

therefore, ∆AMP congruent ∆ANP-------(1)

Angle NAP= angle PAM ( CPCT- eq. 1)

therefore, AP bisects angle BAC

Answer 2

Step-by-step explanation:

the solutions is perfectly right