Question

in the figure point d is the midpoint of side BC and their. g the centroid of triangle ABCfind,a(∆ agd ) a(∆ abd )

Answer 1

Answer:

R.E.F image

Given,

'D' is the midpoint of side BC.

'G' is the centroid of

△ ABC.

also given,

to find out,

ar(△ABD)ar(△AGB)

as 'D' is the midpoint of BC

we get,BD=DC

'G' is the centroid of △ABC.

since we know that,

centroid divides a median in 2:1 ratio

we get,

AG:GD=2:1

as in the given figure ,

the two triangles △ ABD and △AGB

have the same base of line and the

common verier ,so their ratio of

the triangles area will be equal to their

base ratio

so we get,

ar(△ABD)ar(△AGB)=ADAG⇒AG+GDAG

⇒2+12⇒32

ar(△ABD)(△AGB)=32