In the figure , PQ = 11 , PR = 61 and QR = 60 complete the following activity to determine whether ∆ PQR is a Q 60 right angled triangle or not ......... PQ = 11 , QR = 60 and PR = 61
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To prove that
We know that,
h² = p²+b²
PR = PQ + QR
61² = 11²+60²
3721 = 121 + 3600
3721 = 3721
So, by this we can say that ∆ PQR is Right Angled at Q. Because PR is it's Hypotenuse.
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