Question

In the figure , PQ = 11 , PR = 61 and QR = 60 complete the following activity to determine whether ∆ PQR is a Q 60 right angled triangle or not ......... PQ = 11 , QR = 60 and PR = 61​

Answer 1

Answer:

In △PQR,∠PQR=90

∘

BY Pythagoras theorem,

PR

2

=PQ

2

+QR

2

⇒(5)

2

=PQ

2

+(4)

2

⇒(5)

2

−(4)

2

=PQ

2

⇒PQ

2

=25−16

⇒PQ

2

=9

⇒PQ=

9

⇒PQ=3

tanR=

QR

PQ

=

4

3

Step-by-step explanation:

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Answer 2

Answer:

PQ = 11, QR = 60 and PR = 61.

PQ² = 11² = 121.

QR² = 60² = 3600.

PR² = 61² = 3721.

PQ² + QR² = 121 + 3600 = 3721.

PQ² + QR² = PR²

∆PQR is a right angled triangle.