Question

In the figure PQ =24, OR =26, angle PAR =90॰, PA =6, AR = 8 . Find angle QPR.
FIGURE IS NOT GIVEN
PLEASE DRAW THE DIAGRAM YOURSELF ​

Answer 1

PYTHAGORAS THEOREM: In a right angle triangle the square of the hypotenuse is equal to the sum of the square of the other two sides.

CONVERSE OF PYTHAGORAS THEOREM: In a triangle if square of one side is equal to the sum of the squares of the other two sides then the angle opposite to first side is a right angle.

SOLUTION:

Given :

PQ = 24cm ,QR = 26cm, ∠ PAR = 90°, PA = 6cm and AR = 8cm

In ∆ PAR,

PR² = AR² + AP²

[By Pythagoras theorem]

PR² = 8² + 6²

PR² = 64 +36

PR² = 100

PR = √100

PR = 10 cm

In ∆ QPR

QR² = QP² + PR²

26² = 24² + 10²

26² = 576 + 100

26² = 676

676 = 676

∠QPR = 90°

[By Converse of Pythagoras theorem]

Hence the value of ∠QPR = 90°.

HOPE THIS WILL HELP YOU....

Answer 2

Answer:

I think the answer is 90 °