Question

In the figure, PQ = 42 cm. QR is the tangent to the semi circle at Q. If the difference of the areas of regions A,
B is 357, then the base QR of the right triangle PQR is (in cm). Take = 22 꼭​

Answer 1

Step-by-step explanation:

given, area of region A - area of region B = 357

A = 357 + B =: B = A - 357

PQ = 42 cm

in triangle,area of triangle = area of semicircle- area of region B + area of region A

( 1/2 × 22/7 × 21 × 21 ) - ( A - 357 ) + A

area of triangle= 693 - A +357 + A

1/2 ×QR × 42 = 10 50

21 × QR = 1050

QR = 1050 / 21

QR = 50 cm