Question

In the figure, PQ is a tangent to the circle with centre O at the point of contact A.
If ∠BAQ = 60°, find ∠ACB

Answer 1

angle OAQ = 90 ( Radius subtends an angle of 90 at tangent)

angle OAB + angle BAQ = 90

Angle OAB = 30

angle OAB = angle OBA ( Angles opposite equal sides are equal )

Join OC

angle OCB = angle OBA = 30

( Angles on same segment OB)

Similarly

angle OCA = angle OBA = 30

angle ACB = Angle OCA + Angle OCB

= 30+30

= 60

Answer 2

Answer:

Step-by-step explanation:

no it should be 120 degrees

bcoz angle of chord with the tangent is 60 angle substended at major segment should be 60 degrees

angle substended at major + angle substended at minor = 180

60+a=180

a=120