Question

in the figure PQ is parallel to Rs angle A = 95 degree angle b h s = 110 degree and Angle ABC = X degree find the value of x​

Answer 1

Step-by-step explanation:

if AEF is 95° then EGH is also 95°

AB is a line therefore have 180° at AGB

So 180°-95°= 85° so BGH is 85°

similarly RS is a line and have 180° at H

So 180°-110° = 70°

so angle BHG *is 70°

in ∆BHG sum of all angles is 180°

angle BGH is 85°

angle BHG is 70°

therefore the third angle is 180-85+70= 25

so angle ABC is common in both GBH and ABC and the value is 25°