in the figure,pq is the diameter of the circle with centre o and os is parallel to qr.if angle qrs=110, find angle spq and angle pqs and angle psr
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angle SRQ = 110
m(arc SPQ)=2×110.......INSCRIBED ANGLE
= 220
M(ARC SPQ)+M (ARC SRQ)=360
220 + M (ARC SRQ) =360
M (ARC SRQ)= 360-220
M (ARC SRQ)= 140
M ANGLE SPQ = 1/2 ×140
= 70
m(arc SPQ)=2×110.......INSCRIBED ANGLE
= 220
M(ARC SPQ)+M (ARC SRQ)=360
220 + M (ARC SRQ) =360
M (ARC SRQ)= 360-220
M (ARC SRQ)= 140
M ANGLE SPQ = 1/2 ×140
= 70
vaishnavi1803:
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