In the figure, PQ ∥ RS, BA ⊥ PQ and ∠PAC = 137° Find ∠ACS, ∠BAC, ∠ACB.
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HAPPY RAKSHA BANDAN TO ALL BRO AND SIS
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<PAC = <ACS = 137° (Alternate opposite angles)
<BAC + <PAB = 137°
<BAC + 90° = 137°
<BAC = 47°
<ACB + <ACS = 180° (Linear pair)
<ACB + 137° = 180°
<ACB = 43°
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