Question

in the figure PQ || SR, SP is perpendicular to PQ, PQ = 60 cm l, SR = 36cm and QR = 25cm. Find the area of quadrilateral PQRS​

Answer 1

draw a perpendicular from RT to the line segment PQ. TQ=60-36=24cm.

by applying Pythagoras theorem RT=7cm.

area of figure=area of rectangle +area of right triangle =(36×7)+(24×7÷2)

=252+84

= 336sq units. ans.

Answer 2

Answer:

Step-by-step explanation:

i hope this will useful to u

u can take to find area of the Quadrilateral = area of PTRS rectangle + area of the triangle TQR

= length*breadth+ base*height/2

=(36*7)+(24*7)/2

=252+84

=336sq units