In the figure, PQ = XY. PR = XI and QR = YZ. Find
the value of o and a respectively.
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PQ = XY
so, <PRQ = <XZY = 40°
PR = XZ
so, <PQR = <XYZ = 35°
QR = YZ
so, <QPR = <YXZ. = x° ( not given )
now,
p-20° = 35°
so, p = 55°
x° = [180° - (35°+40°)]
= (180° - 75°)
so, x° = 105°
or, q-10° = 105°
so, q = 115°
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